The graph of the required line [tex]\bold{y=\frac{x}{4}+2}[/tex] is given below.
Slope point form of equation of line: -
An equation of line with slope m and passing through point (p, q) is:
(y - q) = m × (x - p)
We have been given the slope of the line m = 1/4,
and a point (p, q) = (0, 2)
Using the slope-point form equation of line would be,
⇒ (y - 2) = 1/4 × (x - 0)
⇒ (y - 2) = 1/4(x)
⇒ y = x/4 + 2 ...............................(1)
So, the equation of the line is [tex]y=\frac{x}{4} +2[/tex].
To plot the line we need at least two coordinate points.
We have been given a point (0, 2).
We need to find another point.
Substitute x = -4 in equation (1),
⇒ y = (-4)/4 + 2
⇒ y = -1 + 2
⇒ y = 1
So, another point on the line would be (-4, 1).
Now, we plot points (0, 2) and (-4, 1) on coordinates plane.
Then the graph of the line [tex]\bold{y=\frac{x}{4}+2 }[/tex] is as shown in figure.
Learn more about the graph of a line here:
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