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What is the rate of acceleration of a hammer whose head goes from moving -2 m/s (downward) to +0.5 m/s (upward) when it hits and bounces off a hard rock ? The actual bounce takes 0.025 seconds

Respuesta :

Answer:

[tex]a=100\ m/s^2[/tex]

Explanation:

Given that,

Initial velocity, u = -2 m/s

Final velocity, v = =.5 m/s

Time, t = 0.025 s

We need to find the rate of acceleration of a hammer. Acceleration is equal to the change in velocity divided by the time taken.

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0.5-(-2)}{0.025}\\\\a=100\ m/s^2[/tex]

So, the acceleration of the jet is [tex]100\ m/s^2[/tex].

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