Answer:
Vf = 25.7 [m/s]
Explanation:
To solve this problem we must use the following kinematics equation:
[tex]v_{f} ^{2}= v_{i} ^{2}-(2*a*x)[/tex]
where:
Vf = final velocity [m/s]
Vi = initial velocity = 30 [m/s]
a = desacceleration = 2 [m/s^2]
x = distance = 60 [m]
Note: the negative sign in the equation means that the car slows down.
Now replacing:
[tex]v_{f}^{2}=(30)^{2}-(2*2*60)\\ v_{f}^{2} = 660\\v_{f} =\sqrt{660} \\v_{f}=25.7[m/s][/tex]
