Respuesta :
The graph for y= √x+1 is shown below.
What is the square root function?
The square root function f(x)=√x has domain [0,∞) with range [0,∞).
Similarly the given function is y=f(x)= √x+1
From the graph, it is clear that the function is valid for x≥0 because x<0 √x will be imaginary.
So the domain of the function f(x)= √x+1 will be [0,∞).
As we know,
√x ≥0
⇒ √x+1≥0+1
⇒√x+1 ≥ 1
⇒f(x) ≥ 1
the function f(x) has range [1,∞).
f(x)=√x+1 ha y intercept at x=0
f(0)= √0+1=1
f(x) has y intercept at (0,1).
Function F(x) will increase from point (0,1).
Therefore The graph for y= √x+1 is shown below.
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