Answer:
[tex]h(x)=6x^2+4x[/tex]
Step-by-step explanation:
As the rectangle's length, f(x), is 2 more than three times a unit length, x, so,
f(x)=3x+2
As the rectangle's width, g(x), is twice the unit length, x, so,
g(x)=2x.
The length and width of the rectangle are related to the area and the perimeter of the rectangle. So, the length, f(x), and the width, g(x), can be combined to give the area or perimeter, h(x).
So, h(x) might be the area or the perimeter of the rectangle.
If h(x) is the area, then
[tex]h(x)=f(x) \times g(x)[/tex] [as area=lenght x width]
[tex]\Rightarrow h(x)=(3x+2)\times 2x[/tex]
[tex]\Rightarrow h(x)=6x^2+4x[/tex] (this is in the given options)
If h(x) is the perimeter, then
[tex]h(x)=2\{f(x) + g(x)\}[/tex] [as perimeter=2(lenght + width)]
[tex]\Rightarrow h(x)=2\{(3x+2)+ 2x\}[/tex]
[tex]\Rightarrow h(x)=2(5x+2)[/tex]
[tex]\Rightarrow h(x)=10x+4[/tex] (not in the given options)
So, from the given options [tex]h(x)=6x^2+4x[/tex] is correct.
Answer:
h(x) = 6x^2 + 4x
Step-by-step explanation:
Got it right on lesson.
