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The standard reduction potentials for two half-cells involving iron are: given below. Fe2+ (aq) + 2e– ® Fe (s) Eο = –0.44 V Fe3+ (aq) + e– ® Fe2+ (aq) Eο = +0.77 V What is the equation and the cell potential for the spontaneous reaction that occurs when the two half-cells are connected?

Respuesta :

Answer:

Explanation:

Fe⁺² (aq) + 2e⁻ =   Fe (s)   ;   E⁰ =  - .44 V

Fe⁺³ (aq) + e⁻ =  ® Fe²⁺ (aq) ;   E⁰ = + .77 V

Reduction potential of second reaction is more , so it will take place , ie Fe⁺³ will be reduced and Fe will be oxidised .

So reaction in the combined cell will be

2Fe⁺³ + Fe = 3Fe⁺²

cell potential = .77 - ( - .44 )

= 1.21 V .

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