Respuesta :

Wolfyy

Answer:

  1. x(x - 2)(x + 5)
  2. x = 0, x = 2, x = -5

Step-by-step explanation:

x^3 + 3x^2 - 10x

~Factor

x(x - 2)(x + 5)

Solve for the zero.

x(x - 2)(x + 5) = 0

We know that; x = 0, x - 2 = 0, and x + 5 = 0

x = 0

x - 2 = 0

x = 2

x + 5 = 0

x = -5

Best of Luck!

FadedElla

Here we are provided with an polynomial of degree 3 and we have to factorise it first and then we have to compute it's zeroes.

Given Polynomial:

  • x³ + 3x² - 10x

Taking common x from all the 3 terms,

➝ x(x² + 3x - 10)

Factorising through Middle term factorisation,

➝ x(x² + 5x - 2x - 10)

➝ x{x(x + 5) - 2(x + 5)}

➝ x(x - 2)(x + 5)

Hence, Factorised !!

Now equating to 0 to find the zeroes of the poly.

➝ x(x - 2)(x + 5) = 0

That means,

  • x = 0
  • x - 2 = 0
  • x + 5 = 0

So, the zeroes of the polynomial is 0, 2 or -5

And we are done....

Carry On Learning [tex]![/tex]

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