Respuesta :

caylus
Hello,

x<0

x-(3/x)<-2
==>x²-3>-2x
==>x²+2x-3>0
==>(x-1)(x+3)>0 so outside the roots
==>(x<0 or x<-3) and x<0
==>x<-3
sol =(-infinite;-3[

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