Step 1) identify the solvent and solute solvent= H2O solute= NaOH Step 2) Assume that there are 100 grams total. Assume that the percent of the compound present is the number of grams present as well 100 g total 16g NaOH 84g H20 Step 3) convert grams to moles 84g H2O =4.64 mol H2O 19 g NaOH = 0.400 mol NaOH Step 4) mole fraction = moles A/(mol A + mol B +....) X= 0.400/(0.400 + 4.64) = 0.079 (no units) Step 5) convert g of solvent to kg 84 g H2O = 0.084 kg Step 6) molality = moles of solute/ kg of solvent molality = 0.400 mol NaOH/ 0.084 kg H2O molality= 4.76 m
