Answer:
Hence x = 2 and y = 7
Step-by-step explanation:
If a parallelogram PQRS has diagonals PR and SQ that intersects at T, then;
T is the midpoint of PR and T is the midpoint of SQ
If T is the midpoint of PR, then PT = TR
Given PT=y and TR=3x+1
y = 3x+ 1 ............ 1
Also, If T is the midpoint of SQ, then ST = TQ
Given QT=3y and TS=4x+13
3y = 4x+ 13 ............ 2
Substitute equation 1 into 2;
3y = 4x+ 13
3(3x+1) = 4x+ 13
open the parenthesis
9x+3 = 4x+13
collect like terms
9x-4x = 13-3
5x = 10
x = 10/5
x = 2
Substitute x = 2 into equation 1
From 1; y = 3x+1
y = 3(2)+1
y = 6+1
y = 7
Hence x = 2 and y = 7
