Respuesta :
Answer:
I = 0.0931 A/cm^2 or 93.1 mA/cm^2
Explanation:
The computation of the corresponding corrosion is shown below:
As we know that
The mathematical form is
[tex]m=\frac{Q}{F} \frac{M}{z}[/tex]
where,
m = substance mass
Q= total electric charge
F= Faradays constant i.e. = 96,500 C/mol
M = Substance molar mass
z = number of electrons transferred
Now
Q = It
where
I = current
And t = time
[tex]m=\frac{Q}{F} \frac{M}{z}[/tex]
So,
[tex]I = \frac{mFz}{tM}[/tex]
Now it is mentioned that
z=3, M=26.98 g/mol, m=0.25 g/cm2
So,
[tex]I= \frac{0.25 g/cm^2 \times 96,500 C/mol \times 3}{((8\times60\times60 s)} \times 26.98 g/mol)[/tex]
Hence,
I = 0.0931 A/cm^2 or 93.1 mA/cm^2
