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A rectangle has a width, w and a length that is 3 more than 2 times longer than the width. Part a) Write an expression for the perimeter of the rectangle. Part b) Write an expression for the area of the rectangle.

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meikelahampton

Answer: Let's write down everything we know: L = 2 + 3W (length is 2 feet more than 3 times the width) A is 16 sq ft A = L x W If we substitute in the area formula so we only have one variable, W: L x W = 16 (2+3W) x W = 16 Multiplying out the paren 2W + 3W^2 = 16 Let's rearrange the terms: 3W^2 + 2W = 16 Subtracting 16 from each side: 3W^2 + 2W - 16 = 0

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