Given :
[tex]n_i=20\\t_i=35\ s\\n_f=100[/tex]
To Find :
Expected time for :
a. O(N)
b. O(N + log N)
c. O(N^3)
d. O(2^N)
Solution :
a.
In O(N) relation is ,
t = kn
So ,
35 = k(20)
t = k(100)
t = 175 seconds .
b .
In O( N + log N ) , N is dominating term . So the complexity is simplified in O(N) .
So , t = 175 seconds .
c .
The relation is given by :
[tex]t=kn^3[/tex]
So ,
[tex]35=k(20)^3\\\\t=k(100)^3\\\\t=35(\dfrac{100}{20})^3\\\\t=4375\ seconds[/tex]
d .
The relation is given by :
[tex]t=k(2)^n[/tex]
So ,
[tex]35=k(2)^{20}\\\\t=k(2)^{100}\\\\t=35\times (2)^{80}[/tex]
Hence , this is the required solution .