Answer:
At the elevation of [tex]617.5[/tex] ft the below sea level of temperature water was [tex]61\frac{1}{20}[/tex]°F
Step-by-step explanation:
Given Information.
[tex]502.5[/tex] ft. below sea level = [tex]63\frac{1}{4}[/tex] °F
Submarine drops [tex]115[/tex] ft deeper so the temperature drops by [tex]2\frac{1}{5}[/tex] ° F
We're looking submarine initial elevation.
Find the elevation the Submarine dove.
[tex](-502.5 )-115=(-617.5)[/tex] ft.
Now find the temperature.
T = [tex]63\frac{1}{4}-2\frac{1}{5}[/tex]
= [tex]\frac{253}{4} - \frac{11}{5}[/tex]
= [tex]\frac{1265-44}{20}[/tex]
= [tex]\frac{1221}{20}[/tex]
= [tex]61\frac{1}{20}[/tex]
