Answer:
Sine rule states that the ratio of a side of a triangle to the angle opposite the side is equivalent for all 3 sides and their respective opposite angles.
[tex]\boxed{ \frac{sinA}{a} = \frac{sinB}{b} = \frac{sinC}{c} }[/tex]
Thus, the side opposite ∠B is side AC, which is 10 units long. The side opposite ∠A is side BC, which is 8 units long. Substitute these values into the formula. (We are at line 2 of working)
Line 3: multiply both sides by 10 to find sinB
This would give us
[tex] sinB = \frac{10sin34°}{8} [/tex]
This is can also be written as: (as seen in line 4)
[tex]sinB = \frac{10}{8}( sin34°)[/tex]
To find the measure of angle B:
[tex]m∠B = sin^{ - 1} ( \frac{10sin34°}{8} ) \\ m∠B = 44° \\ (nearest \: degree)[/tex]
~ Explanation for line 6 and onwards~
The sine of an angle is positive in quadrants I and II. Since sinB is positive (≈0.69899), we are looking at these 2 quadrants. Since the reference angle is 44° rounded off to the nearest whole degree, in quadrant I, the angle would be 44° too.
In quadrant 2, the angle would be 180° -44°= 136°.
