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Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation. If y varies inversely as the square of x, and y=7/4 when x=1, find y when x=3

Respuesta :

Answer:

y=7/36

Step-by-step explanation:

Since y varies inversely to the square of x, we can say

[tex]y = z/x^2[/tex]

where z is the constant of variation.

Then, from knowing that y=7/4 when x=1, we plug them in to find z.

[tex]7/4=z/(1^2)\\z=7/4[/tex]

Now we have the full equation,

[tex]y=7/4x^2[/tex]

Plug x=3 in and we get,

[tex]y=7/4(3^2) = 7/36[/tex]

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