The code below is in Java
It uses if-else structure to find out the largest number among three numbers given by the user.
Comments are used to explain each line of the code
//Main.java
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
//Create a Scanner object to be able to get input
Scanner input = new Scanner(System.in);
//Declare the variables
int number1, number2, number3, largest;
//Ask the user to enter three numbers
System.out.print("Enter the first number: ");
number1 = input.nextInt();
System.out.print("Enter the second number: ");
number2 = input.nextInt();
System.out.print("Enter the third number: ");
number3 = input.nextInt();
/*
Check if the first number is greater than or equal to the second and third number.
If it is, the largest is the first one.
Otherwise, check if the second number is greater than or equal to the first and third number.
If it is, the largest is the second one.
If the previous conditions are not satisfied that means third is the largest one
*/
if(number1 >= number2 && number1 >= number3)
largest = number1;
else if(number2 >= number1 && number2 >= number3)
largest = number2;
else
largest = number3;
//Print the largest number
System.out.println("The largest number is " + largest);
}
}
You may see a similar question in the following link:
brainly.com/question/17132559
