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A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long as 2.20 m have been recorded. If a frog jumps 2.20 m and the launch angle is 46.5°, find the frog's launch speed and the time the frog spends in the air. Ignore air resistance.

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hopemichael95

Answer:

4.7m/s and 0.54s

Explanation:

Using

R= u²sino2စ /g

2.2= u² sin2(46.5)/10

U²= 22

U= √22

=4.7m/s is the launch speed

Then time

T= 2usinစ/g

= 4.7*2sin46.5/10

0.54seconds

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