Given :
y = 9 ln(x) , At the point (1, 0).
To Find :
Equations of the tangent lines to the curve given below at the points specified.
Solution :
Slope of tangent to curve at ( 1, 0) is :
[tex]m=\dfrac{dy}{dx}]\\\\m=\dfrac{d(9\times ln\ x)}{dx}}\\\\m=\dfrac{9}{x}[/tex]
Putting x = 1 , we get :
[tex]m= 9[/tex] .
So , equation of tangent is :
[tex]y-0=9(x-1)\\\\y=9x-9[/tex]
Therefore , this is the required solution .
