Answer:
Han's younger sister accelerated at a rate of 0.5 meters per square second during that time.
Step-by-step explanation:
Let suppose that Han's younger sister accelerates at constant rate, then, acceleration ([tex]a[/tex]), measured in meters per square second, can be calculated by the following equation:
[tex]a = \frac{v_{f}-v_{o}}{t_{f}-t_{o}}[/tex]
Where:
[tex]t_{o}[/tex], [tex]t_{f}[/tex] - Initial and final times, measured in seconds.
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds, measured in meters per second.
If we know that [tex]t_{o} = 3\,s[/tex], [tex]t_{f} = 5\,s[/tex], [tex]v_{o} = 0.5\,\frac{m}{s}[/tex] and [tex]v_{f} = 1.5\,\frac{m}{s}[/tex], the acceleration of the younger sister is:
[tex]a = \frac{1.5\,\frac{m}{s}-0.5\,\frac{m}{s} }{5\,s-3\,s}[/tex]
[tex]a = 0.5\,\frac{m}{s^{2}}[/tex]
Han's younger sister accelerated at a rate of 0.5 meters per square second during that time.
