Answer:
v = 23.6 m/s
d = 78.48 m
Explanation:
Given that,
The initial speed of a car is 20 m/s
Acceleration of the car is 1 m/s²
Time, t = 3.6 s
We need to find the speed and the displacement of the car during this time.
Let v is the speed of the car. So,
[tex]v=u+at\\\\v=20+1\times 3.6\\\\v=23.6\ m/s[/tex]
Let d is the displacement of the car. It can be calculated as follows :
[tex]d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(23.6)^2-(20)^2}{2\times 1}\\\\d=78.48\ m[/tex]
Hence, the speed and the displacement of the car during this time is 23.6 m/s and 78.48 m respectively.
