Respuesta :
cosine rule
[tex]a^2=b^2+c^2-2bc*cos(A)[/tex]
[tex]a^2=35^2+32^2-2*35*32*cos(120)[/tex]
[tex]a^2=3369[/tex]
a is about 58.04
[tex]a^2=b^2+c^2-2bc*cos(A)[/tex]
[tex]a^2=35^2+32^2-2*35*32*cos(120)[/tex]
[tex]a^2=3369[/tex]
a is about 58.04
Answer:
The length of the third side of the triangle is 58 units.
Step-by-step explanation:
A triangle has two sides of length 32 and 35 and that the angle between these two sides is 120°
Using cosine law:
[tex]c^2=a^2+b^2-2ab\cos C[/tex]
where,
a=32
b=35
∠C=120°
Substitute the value into formula and solve c
[tex]c^2=32^2+35^2-2\cdor 32\cdot 35\cos120^\circ[/tex]
[tex]c^2=3369[/tex]
[tex]c=58.04\approx 58[/tex]
Hence, The length of the third side of the triangle is 58 units.