Respuesta :

HomertheGenius
∑ ( from n = 1 to n =5 ) 3 · ( -2 ) ^( n -1 )
a 1 = 3 · ( -2 ) ^0 = 3
a 2 = 3 · ( - 2 ) = - 6
a 3 = 3 · 4 = 12
a 4 = 3 · ( - 8 ) = - 24
a 5 = 3 · 16 = 48
3 - 6 + 12 - 24 + 48 = 33
Answer: C ) 33
boffeemadrid

Answer:

(C)33

Step-by-step explanation:

The given summation can be written as:

[tex]\sum_{n=1}^{5}3(-2)^{n-1}[/tex]

Putting the values of n from 1 to 5 in the above equation, we get

=[tex]3(-2)^0+3(-2)^1+3(-2)^2+3(-2)^3+3(-2)4[/tex]

=[tex]3+(-6)+3(4)+3(-8)+3(16)[/tex]

=[tex]3-6+12-24+48[/tex]

=[tex]33[/tex]

Thus, the value of the given summation [tex]\sum_{n=1}^{5}3(-2)^{n-1}[/tex] is 33.

Hence, option C is correct.

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