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Joe has 20 L of a 2 g/L solution. He diluted it, and created 3 L of a 1 g/L solution. How did he make such a solution?

Respuesta :

Answer:

x = 1.5 L

Explanation:

We're only going to use part of the 20 L. Remember we have to end up with 3 L after dilution, so not only do we have to start with less than 20 L but also less than 3 L. How much is unknown = V1, and it amounts to the same problem as in example 1, but don't use the 20L.

2x=3 divide 2 by both sides

x=3/2=1.5

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