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When solutions containing silver ions and chloride ions are mixed, silver chloride precipitates: Ag+(aq)+Cl−(aq)→AgCl(s)ΔH=−65.5kJ. Calculate ΔH for formation of 0.490mol of AgCl by this reaction.

Respuesta :

Arrhenius acid is acid which gives the H+ and arhenius base is one which donates the -OH group thats why it can identify
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Answer:

The ΔH for the formation of 0.490 mol of AgCl is - 32.095 kJ.

Explanation:

Ag⁺(aq)+Cl⁻(aq)→ AgCl(s) ΔH=−65.5kJ

We need to consider that the value of ΔH given is for each mol of AgCl formed.

1 mol AgCl ________________ - 65.5 kJ

0.490 mol AgCl ____________      x

x = - 32.095 kJ

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