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Using the coordinate plane below. Find the Midpoint of Line Segment EF. Now find the length of Line Segment EF. (Hint: create a right triangle using the two points, count how many units the height and base are, then use the Pythagorean Theorem to find the length of EF. *

Using the coordinate plane below Find the Midpoint of Line Segment EF Now find the length of Line Segment EF Hint create a right triangle using the two points c class=

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ricchad

Answer:

EF = 7.23

mid = -3, 0.5

Step-by-step explanation:

length of line E to F

use Pythagorean

EF = [tex]\sqrt{7^2 + 2^2}[/tex]

EF = 7.23

mid = (x1 + x2)/2 ,  (y1 + y2)/2

mid = (-4 + -2)/2,  (4 + -3)/2

mid = -3, 0.5

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Wolfyy

Pythagorean theorem: c = √a²+b²

In this first part, c will represent the length of EF.

EF = √a²+b²

If we count down and to the right, we can see that we go 7 units down and 2 units right to create the right triangle. We can use those two lengths to find the length of EF.

EF = √7²+2²

EF = √49+4

EF = √53

F = 7.23

Find the mid point

= -4-2/2, 4-3/2

= -6/2, 1/2

= (-3, 0.5)

Best of Luck!

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