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In 1970, a farmer using a two-row combine with a corn head could easily harvest 0.75 ha (1.85 acres) per hour and a typical corn yield was 5000 kg/ha (80 bu/acre). Before 1940, most corn was harvested by hand and a skilled person could harvest 250 kg/h (10 bu/h). Calculate the productivity ratio.

Respuesta :

okpalawalter8

Answer:

The value is [tex]w = 6.7 \%[/tex]

Step-by-step explanation:

Generally the productivity rate is mathematically represented as

[tex]P_r = K * Z[/tex]

Here K is the ha the farmer could harvest in an hour and Z is a typical yield of corn in kg/ha

Now considering 1970

The productivity rate is

[tex]P_r = 0.75 *5000[/tex]

=> [tex]P_r = 3750 \ kg/h [/tex]

Now considering 1940

The productivity rate is given as [tex]P_R = 250 \ kg/h [/tex]

Generally the productivity ratio is mathematically ration is mathematically represented as

[tex]w = \frac{P_R}{P_r} * 100[/tex]

=> [tex]w =  \frac{250}{3750}  * 100[/tex]

=> [tex]w = 6.7 \%[/tex]

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