Respuesta :
Answer:
Concentration of H3O⁺ [H3O⁺] = 0.864 M
Explanation:
Given that:
The mass concentration of MO = 43 g/L
The volume of MO = 7.9 mL = 7.9 × 10⁻³ L
Recall that
The mass number of MO = Mass concentration of MO × Volume of MO
The mass number of MO = (43 g/L) * (7.9 × 10⁻³ L)
The mass number of MO = 0.3397 g
number of moles of MO = (mass number of MO) / (molar mass of MO)
number of moles of MO = (0.3397 g) / (327.33 g/mol)
moles of MO = 0.00104 mol
The total volume = 7.9 mL + 3.13 mL + 5.49 mL + 3.43 mL
The total volume = 19.95 mL = 19.95 × 10⁻³ L
Concentration of MO [MO} =(number of moles of MO) / (total volume)
[MO] = 0.00104 mol / 19.95 × 10⁻³ L
[MO] = 5.2130 × 10⁻⁸ M
the number of moles of H3O⁺ = molarity of HCl in the solution × the volume of HCl in solution
the number of moles of H3O⁺ = [(2.0 M) * (3.13 mL)] + [(2.0 M) * (5.49 mL)]
the number of moles of H3O⁺ = 17.24 mmol
Concentration of H3O⁺ [H3O⁺] = (the number of moles of H3O⁺) / (total volume)
Concentration of H3O⁺ [H3O⁺] = (17.24 mmol) / (19.95 mL)
Concentration of H3O⁺ [H3O⁺] = 0.864 M
The Concentration of H3O⁺ [H3O⁺] is 0.864 M
Calculation of the H3O⁺ concentration:
But before that following calculations should be needed.
The mass number of MO = Mass concentration of MO × Volume of MO
= (43 g/L) * (7.9 × 10⁻³ L)
= 0.3397 g
Now
number of moles of MO = (mass number of MO) / (molar mass of MO)
= (0.3397 g) / (327.33 g/mol)
= 0.00104 mol
Now
The total volume = 7.9 mL + 3.13 mL + 5.49 mL + 3.43 mL
= 19.95 mL
= 19.95 × 10⁻³ L
Now
Concentration of MO [MO} =(number of moles of MO) / (total volume)
= 0.00104 mol / 19.95 × 10⁻³ L
5.2130 × 10⁻⁸ M
Now
the number of moles of H3O⁺ = molarity of HCl in the solution × the volume of HCl in solution
= [(2.0 M) * (3.13 mL)] + [(2.0 M) * (5.49 mL)]
= 17.24 mmol
Now
Concentration of H3O⁺ [H3O⁺] = (the number of moles of H3O⁺) / (total volume)
= (17.24 mmol) / (19.95 mL)
= 0.864 M
Hence, The Concentration of H3O⁺ [H3O⁺] is 0.864 M
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