Answer:
A) 5.5 m/s
B) 9.2 m/s
Explanation:
A) Given in the y direction:
Δy = 2.75 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
2.75 m = (0 m/s) t + ½ (9.8 m/s²) t²
t ≈ 0.75 s
Given in the x direction:
Δx = 4.1 m
a = 0 m/s²
t = 0.75 s
Find: v₀
Δx = v₀ t + ½ at²
4.1 m = v₀ (0.75 s) + ½ (0 m/s²) (.75 s)²
v₀ ≈ 5.5 m/s
B) Find vᵧ.
v² = v₀² + 2aΔy
vᵧ² = (0 m/s)² + 2 (9.8 m/s²) (2.75 m)
vᵧ ≈ 7.34 m/s
Find v.
v² = vₓ² + vᵧ²
v² = (5.5 m/s)² + (7.34 m/s)²
v ≈ 9.2 m/s
