PLEASE HELP!!!!!!!!!!!!!!!!! | For what values of y does the following equation have no solutions for x? | xy + 5y + 4x + 20=1

Respuesta :

Answer:

  y = -4

Step-by-step explanation:

We can solve for x to see.

  x(y+4) +5y +20 = 1

  x(y +4) = -19 -5y . . . . . subtract 5y+20

  x = (-19 -5y)/(y +4)

x is undefined (no solution) for y = -4.

Answer:

y = -4

Step-by-step explanation:

If we look at xy + 5y, we see that both terms share a factor of y. This gives us

                                                   y(x + 5) + 4x + 20 = 1

Similarly, 4x and 20 share a factor of 4, giving us

                                                   y(x + 5) + 4(x + 5) = 1

Now we see that these two terms share a factor of x + 5, so factoring gives us

                                                   (y + 4)(x + 5) = 1

Dividing both sides by y+4 gives us

                                                    x + 5 = 1/(y + 4)

Finally, we subtract both sides by 5 to get

                                                    x = 1/(y + 4) - 5

Thus, since we can not have a 0 in the denominator, we see that if y = -4 then x will have no solution. For any other value of y, we can find the solution for x using this equation.