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Anona hires a decorator to redecorate her bedroom. The decorator offers her 2 different plans: the basic plan has
x wall-color options, x + 1 ceiling-color options, and x + 3 flooring options. The gold plan offers all of the basic plan
offerings, plus 3 additional options in each category.
If a layout includes a wall color, ceiling color, and flooring, which option correctly shows the comparison between the
total number of unique layouts offered by the basic and gold plans?
O 3x +4 < 3x +11
Ox3+4x2 + 3x < 6x + 42x2 + 72
Ox+4 Ox3+4x² + 3x < x + 13.x2 + 54x + 72
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Respuesta :

Answer:

The correct option is;

x³ + 4·x² + 3·x  < x³ + 13·x² + 54·x + 72.

Step-by-step explanation:

The given parameters are;

The basic plan of the decorator = x wall-color options, x + 1 ceiling-colr options, and x + 3 floor options

The gold plan of the decorator = All of the basic plan options plus 3 additional options in each category

Therefore, the gold plan of the decorator = (x + 3) wall-color options, (x + 1 + 3) ceiling-color options, and (x + 3 + 3) floor options

The total number unique layouts offered by the basic plan = x × (x + 1) × (x + 3) = x³ + 4·x² + 3·x

Also, the total number unique layouts offered by the gold plan = (x + 3) × (x + 1 + 3) × (x + 3 + 3) = (x + 3) × (x + 4) × (x + 6)  = x³ + 13·x² + 54·x + 72

Which gives;

The comparison between the total number of unique layouts offered by the basic and gold plans  as x³ + 4·x² + 3·x  < x³ + 13·x² + 54·x + 72.