contestada

Simple Harmonic Motion: The quartz crystal in a digital watch has a frequency of 32.8 kHz. What is its period of oscillation

Respuesta :

Answer:

Time Period of Oscillation = 3.04 x 10⁻⁵ s

Explanation:

The time period of oscillation and the the frequency of oscillation are two inter linked quantities. They are actually the reciprocals of each other. So, the time period of oscillation of quartz crystal is given by the following formula:

Time Period of Oscillation = 1/Frequency of Oscillation

where,

Frequency of Oscillation = 32.8 KHz

Frequency of Oscillation = 32800 Hz

Therefore,

Time Period of Oscillation = 1/32800 Hz

Time Period of Oscillation = 3.04 x 10⁻⁵ s