Answer:
The amplitude of the induced emf is [tex]\epsilon_a = 2.45*10^{-4}\ V[/tex]
Explanation:
From the question we are told that
The area is [tex]A = 8.8 \ mm^2 = 8.8 *10^{-6} \ m[/tex]
The number f turns per cm is [tex]N = 818 \ turn/cm = 81800 \ turn /m[/tex]
The current is [tex]I = 1.28 \ A[/tex]
The angular frequency is [tex]w = 212 \ rad /s[/tex]
Generally the amplitude of the induced emf is mathematically represented as
[tex]\epsilon_a = \mu_o * N * I * w * A[/tex]
Where [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
=> [tex]\epsilon_a = 4\pi * 10^{-7} * 81800 * 1.28 * 212 * 8.8*10^{-6}[/tex]
[tex]\epsilon_a = 2.45*10^{-4}\ V[/tex]
