Answer:
1. 5'AUGCGCUAUCCGUUUAA3'
2. No
Explanation:
1. Considering the base-pairing rule, the substitution of the thymine base in DNA with Uracil base in the corresponding mRNA, and the directionality in DNA/RNA; the corresponding mRNA sequence from the DNA strand 3'TACGCGATAGGCAAATT5' would be: 5'AUGCGCUAUCCGUUUAA3'
2. A codon is made up of 3 nucleotide bases. There are 17 nucleotide bases in the mRNA and if the last codon is a stop codon, it means 14 nucleotide bases would be translated. When 14 is divided by 3, there would be 4 complete codons and 2 nucleotide bases would remain. Hence, the mRNA cannot code correctly for a five amino acid protein.
Answer:
5'AUGCGCUAUCCGUUUAA3'
No, the mRNA strand code will not have a five amino acid protein.
1 Explanation:
Use this formula and it can not be the other way around unless stated:
T translates to A
A translates to U
G translates to C
C translates to G
Because the congruent strand is reciprocal to the mRNA strand, the original 3' - 5' would need to be flipped to 5' - 3'
Thus the answer for 1. is 5'AUGCGCUAUCCGUUUAA3'
2. Explanation:
Let's break the sequence into codons.
AUG - CGC - UAU - CCG - UUU - AA
AUG states for the start point so it doesn't count as a five amino acid protein, thus eliminating it.
CGC - UAU - CCG - UUU - AA
As stated in the question, the last codon is the stop codon, thus eliminating that as well.
CGC - UAU - CCG - UUU
Now the remaining codon would be only 4, not five thus it wouldn't have five amino acid proteins.
Hope this helps!
