Answer:
E. In the external circuit, elections flow from the other compartment to the Cu^2+|Cu^+ compartment
Explanation:
In a galvanic cell, electrons flow from anode to cathode. We must remember that oxidation occurs at the anode and reduction occurs at the cathode. Hence the process; M(s) -------> M^+(aq) + e occurs at the anode.
The electrons lost at the anode are conveyed to the cathode where they are accepted by other chemical species and are reduced to the corresponding reduced species according to the reaction; M^+(aq) + e -----> M(s)
Hence the Cu^2+ | Cu^+ half cell, being the cathode accepts electrons from the other half cell for this reduction reaction to take place, hence the answer
