Answer:
Explanation:
The change in the trucks kinetic energy is same as the net work done by the truck in covering the said distance
Given data
mass of truck m= 1890 kg
initial velocity of truck u1= 34 km/h
final velocity v1= 62 km/h
applying the kinetic energy formula we have
[tex]K.E= \frac{1}{2}mv^2[/tex]
K.E(initial)
[tex]K.E(initial)= \frac{1}{2}*1890*34^2\\\\ K.E(initial)= \frac{1}{2}*1890*1156\\\\ K.E(initial)= \frac{1}{2}*2184840\\\\ K.E(initial)= 1092420J\\\\\ K.E(initial)= 1092.4kJ[/tex]
K.E(final)
[tex]K.E(initial)= \frac{1}{2}*1890*62^2\\\\ K.E(initial)= \frac{1}{2}*1890*3844\\\\ K.E(initial)= \frac{1}{2}*7265160\\\\ K.E(initial)= 3632580J\\\\\ K.E(initial)= 3632.58kJ[/tex]
The change in K.E= K.E(final)- K.E(initial) = 3632.58-1092.4= 2540.18 kJ
the change in the truck's K.E is 2540.18 kJ
