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The three incoming currents at a
node in an electrical circuit
measure 0.38 amps, 0.75 amps,
and 0.29 amps. Two of the three
outgoing currents measure 0.48
amps and 0.6 amps. Find the
measure of the third outgoing
Current


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The three incoming currents at anode in an electrical circuitmeasure 038 amps 075 ampsand 029 amps Two of the threeoutgoing currents measure 048amps and 06 amps class=

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Answer:

Measure of the third outgoing current will be 0.34 ampere.

Step-by-step explanation:

Kirchhoff's Current Law states that total current entering a circuit's junction is exactly equal to the total current leaving the same junction.

By this rule,

Sum of input three currents = Sum of three outgoing currents

0.38 + 0.75 + 0.29 = 0.48 + 0.6 + i

1.42 = 1.08 + i

i = 0.34

Therefore, measure of the third outgoing current will be 0.34 ampere.

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