Answer:
[tex]3 \sqrt 5}[/tex] and [tex]-3 \sqrt 5}[/tex]
Step-by-step explanation:
Given
[tex]x^2 = 45[/tex]
Required
Determine the values of x
[tex]x^2 = 45[/tex]
Take square root of both sides
[tex]\sqrt{x^2} = \±\sqrt{45}[/tex]
[tex]x = \±\sqrt{45}[/tex]
Expand 45 as 9 * 5
[tex]x = \±\sqrt{9 * 5}[/tex]
Split the square root
[tex]x = \±(\sqrt{9} *\sqrt 5}[/tex]
[tex]x = \±3 *\sqrt 5}[/tex]
[tex]x = \±3 \sqrt 5}[/tex]
This can be further split to:
[tex]x = 3 \sqrt 5}[/tex] or [tex]x = -3 \sqrt 5}[/tex]
Hence, the possible values of x are
[tex]3 \sqrt 5}[/tex] and [tex]-3 \sqrt 5}[/tex]
