Respuesta :
First multiply the numbers inside the radicals together.
So √3 · √15 is √45.
So we have 2√45.
Note that the 2 can't be multiplied by anything since
√15 has nothing outside of the radical.
So we have 2√45.
Now, break down your square root.
√45 breaks down as 9 · 5 and 9 breaks down as 3 · 3.
Since we have a pair of 3's, a 3 comes outside of the radical
multiplying by the 2 that was previously outside to get 6.
The 5 doesn't pair up so it stays inside.
So our final answer is 6√5.
Answer:
C) [tex]6\sqrt{5}[/tex]
Arithmetic without explanation:
[tex]2\sqrt{3}* \sqrt{15}\\ = 2\sqrt{3}* \sqrt{3*5} \\ = 2\sqrt{3^2} *\sqrt{5} \\ = 2 * 3\sqrt{5} \\= 6\sqrt{5}[/tex]
Example of radical multiplication:
Take [tex]y\sqrt{x} * a\sqrt{b}[/tex] as an example:
1. Multiple the numbers inside the roots
[tex]\sqrt{x} * \sqrt{b} = \sqrt{x*b} = \sqrt{xb}[/tex]
2. Multiple the numbers outside the roots
[tex]y*a = ya[/tex]
3. Combine them and simplify
[tex]ya\sqrt{xb}[/tex]
Step-by-step explanation:
We are given the expression [tex]2\sqrt{3}*\sqrt{15}[/tex]
1. Identify the roots and multiply them
The roots are [tex]\sqrt{3}[/tex] and [tex]\sqrt{15}[/tex]
[tex]\sqrt{3} *\sqrt{15} \\= \sqrt{45}[/tex]
2. Multiply the numbers outside the root
For [tex]2\sqrt{3}[/tex] it is [tex]2[/tex] and for [tex]\sqrt{15}[/tex] it is [tex]1[/tex]
[tex]2*1 = 2[/tex]
3. Combine and simplify
Combine:
[tex]2* \sqrt{45}\\= 2\sqrt{45}[/tex]
Simplify:
*Note: [tex]\sqrt{n^2} = n[/tex]
1. Find the Prime factorization of 45
[tex]45 = 3^2 * 5[/tex]
2. Simplify the Root
[tex]2\sqrt{45} \\ = 2\sqrt{3^2 * 5} \\= 2\sqrt{3^2} * \sqrt{5} \\= 2 * 3\sqrt{5}\\ =6\sqrt{5}[/tex]
We end up with [tex]6\sqrt{5}[/tex]
