Answer:
B = 0.157 T
Explanation:
Given that,
Length of the solenoid, l = 8 cm = 0.08 m
Number of turns in the wire, N = 2000
Current, I = 5 A
We need to find the strength of the magnetic field at the center of the solenoid. It is given by the formula as follows :
[tex]N=\mu_o nI[/tex], N is number of turns per unit length of solenoid.
So,
[tex]B=4\pi \times 10^{-7}\times \dfrac{2000}{0.08}\times 5\\\\=0.157\ T[/tex]
So, the magnetic field at the center of the solenoid is 0.157 T.
