Answer:
288 Joules
Explanation:
Work= delta kinetic energy. To find the work required to stop the kitten, you have to find the delta kinetic energy between when the kitten is moving and when it is stopped. Since it is not moving when it's stopped, it has no kinetic energy. So to find the work, just find the kinetic energy of the kitten moving at 12m/s.
KE=1/2((m)(v^2)), therefore
delta KE=(1/2)*((4kg)*((12m/s)^2))-0
The work done must this force do to stop the kitten will be "288 Joules". To understand the calculation, check below.
According to the question,
Mass of kitten, m = 4 kg
Speed, v = 12 m/s
Acceleration, a = 3 m/s²
We know the formula,
→ Kinetic energy, K.E = [tex]\frac{1}{2}[/tex] mv²
then,
→ ΔK.E = [tex]\frac{1}{2}[/tex] mv² - 0
By substituting the values, we get
= [tex]\frac{1}{2}[/tex] × 4 × (12)² - 0
= [tex]\frac{1}{2}[/tex] × 4 × 144 - 0
= 2 × 144
= 288 Joules
Thus the above response is correct.
Find out more information about work done here:
https://brainly.com/question/25923373
