Answer:
Hey there!
For question 1:
C(11,5) = (11!)/(5!*(11-5)!)
C(11,5) = (11!)/(5!*6!)
C(11,5) = (11*10*9*8*7*6!)/(5!*6!)
C(11,5) = (55440)/(120)
C(11,5) = 462 ways
For question 2:
10!=10*9*8*7*...*2*1= 3628800 ways.
This can be a challenging and confusing topic, so let me know if you want a easier to understand explanation, I'm always here to give one :)
A number of ways to choose the players are 462 and The coach made a batting order is 3,268,800.
A permutation is an act of arranging the objects or elements in order.
1. Rylan's basketball team has 11 players.
His coach chooses five starting players.
The number of different ways to choose the players.
[tex]\rm ^{11}C_{5} = \dfrac{11!}{5! (11-5)!} = 462[/tex]
2. Sarah plays softball over the summer. If there are 10 players on the team.
The coach made a batting order that will be
[tex]10! = 10*9*8*7*6*5*4*3*2*1 = 3268800[/tex]
Thus, A number of ways to choose the players are 462 and The coach made a batting order is 3,268,800.
More about the permutation link is given below.
https://brainly.com/question/1216161
