Answer:
The answer is
[tex]x = \frac{ {e}^{ \frac{3}{ ln(2) } } }{4} [/tex]
Step-by-step explanation:
[tex] ln(2) \times ln(4x) = 3[/tex]
Divide both sides of the equation by ln 2
That's
[tex] \frac{ ln(2) ln(4x) }{ ln(2) } = \frac{3}{ ln(2) } [/tex]
We have
[tex] ln(4x) = \frac{3}{ ln(2) } [/tex]
Covert the logarithm into exponential form using the property
[tex] ln(x) = b
\: \: is \: \: \: the \: \: \: same \: \: \: as \: \: \: \:
x = {e}^{b} [/tex]
Are all the same
So
[tex] ln(4x) = \frac{3}{ ln(2) } [/tex]
is the same as
[tex]4x = {e}^{ \frac{3}{ ln(2) } } [/tex]
Divide both sides by 4
We have the final answer as
[tex]x = \frac{ {e}^{ \frac{3}{ ln(2) } } }{4} [/tex]
Hope this helps you
