x - the first number,
y - the second number
We have:
[tex]\begin{cases}y=5x\\y+21=2(x+21)\end{cases}\\\\\\\begin{cases}y=5x\\y+21=2x+42\end{cases}\\\\\\\begin{cases}y=5x\\5x+21=2x+42\end{cases}\\\\\\\begin{cases}y=5x\\3x=21\quad|:3\end{cases}\\\\\\\begin{cases}y=5x\\\boxed{x=7}\end{cases}\\\\y=5x\\\\y=5\cdot7\\\\\boxed{y=35}[/tex]
So answer is 7 and 35.