Answer:
Step-by-step explanation:
Hello, first of all we can find a value for f(1)
[tex]xf(x)+f(x^2)=2 \\\\\text{So for x = 1, it gives}\\\\f(1)+f(1^2)=f(1)+f(1)=2f(1)=2\\\\<=> f(1) =1[/tex]
And we can get the derivative of the equation so.
[tex](uv)'=u'v+uv' \text{ and } \dfrac{df(x^2)}{dx}=2xf'(x^2) \text{ so we can write}\\\\f(x)+xf'(x)+2xf'(x^2)=0\\\\\text{And then, for x = 1}\\\\f(1)+f'(1)+2f'(1)=0\\\\<=> f(1)+3f'(1)=0\\\\<=> 3f'(1)=-f(1)=-1\\\\<=>\large \boxed{ f'(1)=-\dfrac{1}{3} }[/tex]
Thank you
