Answer:
The mass of nitrogen molecule [tex]N_2[/tex] = 45.65 g
Explanation:
The equation for the redox reaction can be represented as follows:
[tex]\mathtt{2N_2H_4 +N_2O_4 \ \to \ 3N_2 + 4H_2O}[/tex]
We know that:
numbers of moles = mass/molar mass
For [tex]\mathtt{N_2O_4}[/tex] :
number of moles = 50g/92 g/mol
number of moles = 0.5435 mol
For [tex]\mathtt{N_2H_4}[/tex] :
number of moles = 45 g/ 32 g/mol
number of moles = 1.40625 mol
From the above equation;
number of moles of [tex]\mathtt{N_2O_4}[/tex] needed = 1/2 moles of [tex]\mathtt{N_2H_4}[/tex] = 1/2 × 1.40625 mol
= 0.703125 mol
The amount of [tex]\mathtt{N_2O_4}[/tex] present = 0.5435 moles which is less than the needed. As such [tex]\mathtt{N_2O_4}[/tex] is the limiting reagent
The number of moles of nitrogen molecule [tex]N_2[/tex] produced = 3 × ([tex]\mathtt{N_2O_4}[/tex])
= 3 × 0.5435
= 1.6305 mol
The mass of nitrogen molecule [tex]N_2[/tex] = number of moles of [tex]N_2[/tex] × molar mass of [tex]N_2[/tex]
The mass of nitrogen molecule [tex]N_2[/tex] = 1.6305 mol × 28 g/mol
The mass of nitrogen molecule [tex]N_2[/tex] = 45.654 g
The mass of nitrogen molecule [tex]N_2[/tex] = 45.65 g
