Answer: [tex]\frac{K_{A}}{K_{B}}[/tex] = 1
Explanation: Average molecular kinetic energy for monatomic idela gases is given by:
[tex]E=\frac{3}{2}RT[/tex]
where
R is gas constant of ideal gas
T is temperature
Which means kinetic energy depnends only on temperature.
Since gas A and gas B are at the same temperature, kinetic energy will be the same. Therefore:
[tex]\frac{K_{A}}{K_{B}}[/tex] = 1
Ratio of this average molecular kinetic energy is 1.
