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what is an equation of the line that is perpendicular to y-4 = 2(x-6) and passes through the point (-3, -5)

Respuesta :

meredith48034

Answer:

Step-by-step explanation:

y - 4 = 2x - 12

y = 2x - 8

perp slope: -1/2

y + 5 = -1/2(x + 3)

y + 10/2= -1/2x - 3/2

y = -1/2x - 13/2

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