Answer:
[tex] P(14.8< X<16.5)= \frac{16.5-11.1}{19.2-11.1} -\frac{14.8-11.1}{19.2-11.1}= 0.667-0.457= 0.210[/tex]
The probability that it will require between 14.8 and 16.5 minutes to perform the task is 0.210
Step-by-step explanation:
Let X the random variable "completion times for a job task" , and we know that the distribution for X is given by:
[tex] X \sim Unif (a= 11.1, b= 19.2)[/tex]
And for this case we wantto find the following probability:
[tex] P(14.8< X<16.5)[/tex]
And for this case we can use the cumulative distribution given by:
[tex] F(x) =\frac{x-a}{b-a} , a\leq X \leq b[/tex]
And using this formula we got:
[tex] P(14.8< X<16.5)= \frac{16.5-11.1}{19.2-11.1} -\frac{14.8-11.1}{19.2-11.1}= 0.667-0.457= 0.210[/tex]
The probability that it will require between 14.8 and 16.5 minutes to perform the task is 0.210
