Respuesta :
Answer:
t = ±2.179
Step-by-step explanation:
Given:
Regression equation = Y = 30 + 2.56X
Sample size, n = 14
Standard error, e = 0.97
Significance level, [tex] \alpha [/tex] = 0.05
Required:
Find the critical value
At level of significance = 0.05
Degrees of freedom, df = n - 2 = 14 - 2= 12
Find critical value:
Using t table, two tailed, df = 12, we have:
[tex] t_\alpha_/_2_, _d_f = t_0_._0_2_5_,_1_3 = 2.179 [/tex]
Therefore, the critical value,
t-critical = ±2.179
In this exercise we will use the knowledge of degrees of freedom and the data reported in the exercise to calculate the critical temperature of the system, so:
[tex]t-critical = +/- 2.179[/tex]
Given in the exercise we have to:
- Regression equation: [tex]Y = 30 + 2.56X[/tex]
- Sample size: [tex]14[/tex]
- Standard error: [tex]0.97[/tex]
- Significance level: [tex]0.05[/tex]
in this exercise we want to find the critical value in this way, we will have that it will be:
- At level of significance = 0.05
- Degrees of freedom, df = n - 2 = 14 - 2= 12
Using t table, two tailed, df = 12, we have:
[tex]T_{\alpha /2} , df = t_{0.025,13)= 2.179[/tex]
Therefore, the critical value corresponde to;
[tex]t-critical = +/- 2.179[/tex]
See more about critical temperature at brainly.com/question/14562729